How would you program a recursive solution to find the nth Fibonacci number?
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Question Analysis
The problem requires you to implement a recursive solution to find the nth Fibonacci number. The Fibonacci sequence is a series of numbers where each number is the sum of the two preceding ones, usually starting with 0 and 1. The sequence typically looks like this: 0, 1, 1, 2, 3, 5, 8, and so on. The goal is to compute the nth number in this sequence using recursion, which is a method where the solution to a problem depends on solutions to smaller instances of the same problem.
Answer
To implement a recursive solution for finding the nth Fibonacci number, follow these steps:
- Base Cases:
- If
n
is 0, return 0. - If
n
is 1, return 1.
- If
- Recursive Case:
- For
n >= 2
, the nth Fibonacci number is the sum of the two preceding Fibonacci numbers:fib(n) = fib(n-1) + fib(n-2)
.
- For
Here is a simple implementation in Python:
def fibonacci(n):
# Base cases
if n == 0:
return 0
elif n == 1:
return 1
# Recursive case
else:
return fibonacci(n-1) + fibonacci(n-2)
# Example usage:
n = 5
print(f"The {n}th Fibonacci number is: {fibonacci(n)}")
Explanation:
- The function
fibonacci
takes an integern
as input. - It checks if
n
is 0 or 1, returning 0 or 1 respectively. - For any other value of
n
, it recursively calls itself to compute the sum of the Fibonacci numbers at positionsn-1
andn-2
.
Note:
- This recursive approach is straightforward but not the most efficient for large
n
due to redundant calculations. Consider using memoization or an iterative approach for better efficiency in practical scenarios.