What strategy would you employ to write a function that converts a nested list of integers into a single list, and also its async/await version?
Question Analysis
The question asks you to come up with a strategy to write a function that takes a nested list of integers (i.e., a list containing other lists of integers) and flattens it into a single list of integers. Additionally, you are required to provide an asynchronous version of this function using async/await
. This will test your ability to handle nested data structures and your understanding of Python's asynchronous programming capabilities.
Answer
Synchronous Version
To flatten a nested list, you can use a recursive approach or a stack-based iterative approach. The recursive approach is more straightforward:
- Base Case: If the element is an integer, add it to the result list.
- Recursive Case: If the element is a list, recursively flatten it and add its elements to the result list.
Here's a simple implementation:
def flatten(nested_list):
result = []
for element in nested_list:
if isinstance(element, list):
result.extend(flatten(element))
else:
result.append(element)
return result
Asynchronous Version
To convert this function into an asynchronous one, let's simulate an asynchronous operation (like an I/O-bound task). We can use asyncio.sleep()
to mimic this behavior.
- Mark the function with the
async
keyword. - Use
await
with an asynchronous operation inside the function.
Here's how you can implement it:
import asyncio
async def async_flatten(nested_list):
result = []
for element in nested_list:
await asyncio.sleep(0) # Simulating asynchronous operation
if isinstance(element, list):
flattened = await async_flatten(element)
result.extend(flattened)
else:
result.append(element)
return result
# Usage example
# asyncio.run(async_flatten([[1, 2], [3, [4, 5]]]))
Key Points:
- Synchronous Function: Uses recursion to handle nested structures.
- Asynchronous Function: Introduces async behavior using
await
to handle potential I/O-bound tasks, although this example usesasyncio.sleep()
for demonstration purposes.